Wednesday, June 19, 2019

Soil Mechanics Exercises Math Problem Example | Topics and Well Written Essays - 2500 words

Soil Mechanics Exercises - Math Problem ExampleFrom the chart we have D10 = 0.2D30 = 0.45D60 = 1.20So Coefficient of uniformity is = D60/D30 Cu = 1.20/0.2 = 6.0And Coefficient of curved shape of the soil is = D302/(D10 x D60) Cc = 0.452/(0.2 x 1.2) = 0.84375(iv)From the particle size distribution chart we can see that the particles are distributed over a wide range. So, this is a well graded soil.... 3 (a) At 0 m heart and soul breed= ?= ?d hw +q = 16 (0) + 10 =10 Kpa Pore pressure = u = ?w x (h hw) = 9.81 (0)=0 sound prove = ?= ? u = 10 0 =10 Kpa At 1 m Total stress= ?= ?d hw +q = 16 (1) + 10 = 26 Kpa Pore pressure = u = ?w x (h hw) = 9.81 (0) = 0 Effective stress = ?= ? u = 26 0 = 26 Kpa At 3 m Total stress= ?= ?d hw +q + ?sat (h hw) = 16 + 10 + 20 (2) = 66 KPa Pore pressure = u = ?w x (h hw) = 9.81 x (2) = 19.62 Kpa Effective stress = ?= ? u = 66 19.62 = 46.38 Kpa At 7 m Total stress= ?= ?d hw +q + ?sat (h hw) = 16 + 10 + 20 (6) = 146 KPa Pore pressure = u = ?w x (h hw) = 9.81 x (6) = 58.86 Kpa Effective stress = ?= ? u = 146 58.86 = 87.14 Kpa (b) Unit weight of silty sand = ?s= porosity * specific gravity * 9.81 = 0.54 x 2.61 x 9.81 = 14 kN/m3 Saturated weight of clay =?c= = = 17.82 kN/m3 At 0 m Total stress= ?= ?s h = 14 (0) = 0 Pore pressure = u = ?w x (h hw) = 9.81 (0) =0 Effective stress = ?= ? u = 0 At 2.5 m Total stress= ?= ?s h = 14 (2.5) = 35 KPa Pore pressure = u = ?w x (h hw) = 9.81 x (0) = 0 Effective stress = ?= ? u = 35 - 0 = 35 Kpa At 5 m Total stress= ?= ?s h = 14 x 5 = 70 Kpa Pore pressure = u = ?w x (h hw) = 9.81 x (2.5) = 24.5 kPa Effective stress = ?= ? u = 70 24.5 = 45.5 Kpa At 9 m Total stress= ?= ?s h +?c (h 5) = 14 x 9 + 17.82 (4) = 197.3 KPa Pore pressure = u = ?w x (h hw) = 9.81 x (6.5) = 63.76 Kpa Effective stress = ?= ? u = 197.3 63.76 = 133.54 Kpa Question No. 4 (a) Shear box apparatus The soil is contained in a box which has a separate top half and bottom half. A normal stress is

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